Physics
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Interpret the information contained in the equation below that was used to solve a certain problem:
50 J = −(0.0142 mol)(8.31 J/mol K)(T)Ln(1/5).
50 J of work is done in an isothermal process at 263K that increases volume to 5V0
50 J of work is done in an isothermal process at 263K that increases pressure to 5P0
50 J of heat flows into the gas in an isothermal process at 263K that decreases volume to (1/5)V0
50 J of heat flows into the gas in an isothermal process at 263K that increases pressure to 5P0