Interpret the information contained in the equation below that was used to solve a certain problem:

50 J = −(0.0142 mol)(8.31 J/mol K)(T)Ln(1/5).

50 J of work is done in an isothermal process at 263K that increases volume to 5V₀

50 J of work is done in an isothermal process at 263K that increases pressure to 5P₀

50 J of heat flows into the gas in an isothermal process at 263K that decreases volume to (1/5)V₀

50 J of heat flows into the gas in an isothermal process at 263K that increases pressure to 5P₀