Organic Chemistry
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Using the following equations and values:
H2O ⇌ H+ + OH−
pH + pOH = 14
pH = −log[H+]; pOH = −log[OH−]; pKa = −logKa
[H2O] = 55.5 M
Provide the steps to prove that the pKa of water is 15.7.
Step 1: Set up the acid dissociation constant equation
Step 2: Take the logarithm of both sides
Step 3: Substitute pH for log[H+], pOH for log[OH−], and pKa for logKa
Step 4: Plug in the values of 'pH + pOH' and [H2O] and calculate pKa
Step 1: Set up the base dissociation constant equation
Step 3: Substitute pH for −log[H+], pOH for −log[OH−], and pKa for −logKa
Step 2: Take the negative logarithm of both sides