Taking one molecule of glucose through glycolysis, pyruvate oxidation, and the Krebs cycle generates:
a) 6 CO₂, 8 NADH, 2 FADH₂ and 4 ATP.
b) 6 CO₂, 8 NADH, 1 FADH₂ and 2 ATP. 
c)  6 CO₂, 10 NADH, 2 FADH₂ and 4 ATP.  d) 6 CO₂, 10 NADH, 2 FADH₂ and 2 ATP.

• A. 6 CO₂, 8 NADH, 2 FADH₂ and 4 ATP.
• B. 6 CO₂, 8 NADH, 1 FADH₂ and 2 ATP.
• C. 6 CO₂, 10 NADH, 2 FADH₂ and 4 ATP.
• D. 6 CO₂, 10 NADH, 2 FADH₂ and 2 ATP.

Answer: (C)

Verified step by step guidance

1. Begin by understanding the three main stages of cellular respiration: glycolysis, pyruvate oxidation, and the Krebs cycle. Each stage contributes to the production of CO2, NADH, FADH2, and ATP.
2. In glycolysis, one molecule of glucose (C6H12O6) is broken down into two molecules of pyruvate. This process generates 2 ATP and 2 NADH.
3. During pyruvate oxidation, each pyruvate is converted into acetyl-CoA, releasing one molecule of CO2 and producing one NADH per pyruvate. Since there are two pyruvate molecules, this results in 2 CO2 and 2 NADH.
4. In the Krebs cycle, each acetyl-CoA enters the cycle, resulting in the production of 2 CO2, 3 NADH, 1 FADH2, and 1 ATP per cycle. Since there are two acetyl-CoA molecules, this doubles the output to 4 CO2, 6 NADH, 2 FADH2, and 2 ATP.
5. Add up the totals from all stages: Glycolysis (2 ATP, 2 NADH), Pyruvate Oxidation (2 CO2, 2 NADH), and Krebs Cycle (4 CO2, 6 NADH, 2 FADH2, 2 ATP) to find the overall yield: 6 CO2, 10 NADH, 2 FADH2, and 4 ATP.