When table sugar (sucrose, C12H22O11) is heated, it decomposes to...

Question

When table sugar (sucrose, C12H22O11) is heated, it decomposes to form C and H2O.

Write a balanced equation for the process.

Accepted Answer

Hello. And this problem, we're told that the compound potassium employee decomposes into potassium chloride and oxygen gas grass provides a balanced reaction equation. We have our reactant potassium chloride, which is going to decompose, break down to form potassium chloride and oxygen gas. Frequently we can make use of the subscript To become the coefficient. We have two oxygen's on the product side. three, on the reactive side, we put a two out in front of the potassium chlorate and the three out in front of the oxygen. We now have six oxygen's on both sides. And now we will balance the potassium in the flooring By putting a two out in front of potassium chloride on the product side. This is in our balanced reaction for the decomposition of potassium Floyd. This corresponds to answer. C thanks for watching. Hope this helped.

When table sugar (sucrose, C12H22O11) is heated, it decomposes to form C and H2O. Write a balanced equation for the process.

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