Hey, everyone. So we're going to take a look at acidic hydrolysis of amides. Now we're going to say that under this reaction, an amide is hydrolyzed into a carboxylic acid and an ammonium ion in an acidic medium. Now if we take a look at this general reaction, we have our amide here and with it our amide bond that connects our nitrogen to our carbonyl group. Under this reaction, we use basically aqueous acid, meaning that we have hydrochloric acid dissolved in water, and we accompany it with heat. Basically what happens is that in this reaction, the carbonyl carbon is going to gain a hydroxyl group. Doing this transforms it into a carboxylic acid. And at the same time, we're going to have the nitrogen itself gains 2 hydrogen atoms, and thereby becomes an ammonium ion. Remember when nitrogen makes 4 bonds it becomes positively charged. It transitions from being a neutral amine to an ammonium ion. So just remember under acidic hydrolysis we make a carboxylic acid and an ammonium ion.
Amide Hydrolysis - Video Tutorials & Practice Problems
Acidic Hydrolysis Concept 1
Video transcript
Acidic Hydrolysis Example 1
Video transcript
Determine the products when 3,3-dimethylhexanamide is treated with an aqueous hydrochloric acid solution. So remember, in this reaction, we're going to cut this amide bond. And what's going to occur is that the carbonyl carbon gains an OH group. So, we create a carboxylic acid. At the same time, the nitrogen itself will gain 2 hydrogen atoms. Since nitrogen already contains 2 hydrogens, it's going to gain another 2. So at the end, we'll have 4 hydrogens on the nitrogen. It'll be making 4 bonds, so it'll be positively charged. So here, we make an ammonium ion as the second product. So this would be our answer for this particular example question. We created a carboxylic acid and the ammonium ion.
Name the carboxylic acid formed when the following amide undergoes an acidic hydrolysis reaction.
2-bromopentanoic acid
3-bromohexanoic acid
3-bromopentanoic acid
3-bromohexanoate
Basic Hydrolysis Concept 2
Video transcript
In this video, we're going to take a look at basic hydrolysis of amides. Now, under this reaction, we're going to say that the hydroxide ion, which is OH-, dissolved in water reacts with an amide. The reaction cleaves or cuts the amide bond to create a carboxylate anion and an amine. Now, if we take a look here at this general reaction, we're going to cut this amide bond by using aqueous hydroxide. So that just means it's dissolved in water and accompanied by some heat.
So essentially, what happens here is that the carbonyl carbon will gain an O- because a carboxylate anion is just the conjugate base form of a carboxylic acid. So instead of having an OH group, it has an O minus group. And the nitrogen here would only gain 1 hydrogen atom. Here we create a neutral amine. So under basic conditions, we're not making a carboxylic acid, we're making its conjugate base, which is our carboxylate anion. And for the amine, it's going to be a neutral amine that's being formed.
Basic Hydrolysis Example 2
Video transcript
Determine the products when N-ethyln-methylbutanamide is treated with an aqueous hydroxide ion solution. Now, before we do this question, remember, when it comes to our N substituents, you have to have your N capitalized and italicized. Right. So that's the name of this particular amide. Now, under basic hydrolysis, we're going to cut the amide bond. When we do that, we're going to make a carboxylate anion. So the carbonyl group gets an O negative attached to it, and then the amide, well, the nitrogen part of the amide, that nitrogen, all it's going to do is gain 1 hydrogen and stay as a neutral amine. Right? So in this particular question, we make a carboxylate anion product as well as a neutral amine.
Determine the carboxylate anion formed in the following reaction between the given amide and aqueous base.
Determine the nitrogen product formed when the following amide undergoes acidic hydrolysis.
What was the starting material that created the following products?
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