For the zeroth-order reaction: A → products, what will happen to the rate of reaction if the concentration of A is doubled?

• A. The rate of reaction will quadruple.
• B. The rate of reaction will double.
• C. The rate of reaction will remain the same.
• D. The rate of reaction will decrease by half.

Answer: (C)

Verified step by step guidance

1. Understand the concept of a zeroth-order reaction: In a zeroth-order reaction, the rate of reaction is independent of the concentration of the reactant. This means that the rate is constant and does not change with varying concentrations of the reactant.
2. Identify the rate law for a zeroth-order reaction: The rate law for a zeroth-order reaction can be expressed as: $\mathrm{Rate}=k$, where $k$ is the rate constant.
3. Consider the effect of changing the concentration of reactant A: Since the rate of a zeroth-order reaction is given by the rate constant $k$, it does not depend on the concentration of A. Therefore, doubling the concentration of A will not affect the rate.
4. Compare with other order reactions: In contrast, for first-order reactions, the rate is directly proportional to the concentration of the reactant, and for second-order reactions, the rate is proportional to the square of the concentration. This highlights the unique characteristic of zeroth-order reactions.
5. Conclude the analysis: Based on the understanding of zeroth-order reactions, the rate of reaction will remain the same regardless of changes in the concentration of A.