Carboxylic Acid Reactions - Video Tutorials & Practice Problems
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1
concept
Acid-Base Reaction
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In this video, we're gonna take a look at carbolic acid reactions. Now, here we do this by examining acid base reactions. We're gonna say under this type of reaction, a base reacts with a carbolic acid which represents a weak acid. If we take a look here, we have a carbolic acid in the form of ethanoic acid. Here, we're gonna use some type of base which is going to remove an H plus from the carbolic acid. And in doing this creates its conjugate base form which is a carboxylate anion. Now here the carboxylate an ion, its ending is different in its carbolic acid form. It's OIC acid in its carboxylate, an ion form, you change the OIC acid to 08. So ethanoic acid becomes ethanoic, right? So just remember when we're talking about a carbolic acid reaction, we're basically saying the carbolic acid is an acid, we can tell from its name and it's reacted with some type of base which removes an H plus from it, thereby creating a carboxylate an ion product.
2
example
Carboxylic Acid Reactions Example
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Predict the products form from a f reaction between propo acid and ammonia. Right. So here this is our acid ammonia, which is a neutral nitrogen compound. We know is our weak base. Now, since both of these species are weak, we know that we have reversible arrows to show that an equilibrium has been established. If you don't remember this, make sure you go back and take a look at my videos when we talk about reactions and equilibrium between acids and bases. So we know following the Bronson or definition of acids and bases that the carboy acid gives away an H plus to the ammonia. It becomes a carboxyl anion. In the process, the ammonia gains an H plus to become the ammonium ion. So it becomes NH four positive. So, although we're talking about an organic molecule in terms of carbolic acid, this is kind of familiar because it follows our Boston Laurie definitions of acids and bases, the acid donates in H plus, the base accepts the H plus. And in that way, we make our two ions as products
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Problem
Problem
Name the carboxylate anion formed in the following reaction.
A
2-methylpentanoate
B
4-methylhexanoate
C
4-methylpentanoate
D
2-methylhexanoate
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