Production of Hydrogen - Video Tutorials & Practice Problems
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1
concept
From Ionic Hydrides
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Now, there are several reactions that produce hydrogen gas. We will take a look at two reactions. The first one comes from ionic hydride. Now, ionic hydride can be used as a source for our H two gas molecules. Here, we're going to say due to the basic nature of our hydride ion, it reacts with water or an acid to form H two gas. Here, we have H two from an ionic hydride. An example here, we have it reacting with a metal hydride and some type of acid here. In order to determine what our products will be, we just have to break up our reactants into their respective ions. Here. This would be M two plus that's where this two came from. And then here hydrogen is with the metal. So it's the hydride form. So minus one, our acid here would be H plus one and a minus one. Here, we're gonna do a double displacement reaction. So our minus one H and our plus one H will combine together to give us our H two gas molecule. And then we're gonna say here that the two from our metal is gonna come here and our one from our A minus is gonna come here. That's going to give us ma two. We need to balance this out here. We're going to say we have uh three hydrogens on the reactant side and only two on the product side. I'm gonna put a two here to give us two H two gas molecules giving us a total of four hydrogens on the product side. In addition to this, we have two A atoms. So to balance things out, I put a two here. So this would be an example of us using a metal or ionic hydride with an acid in order to produce H two gas.
2
example
Production of Hydrogen Example
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Here, it says complete and balance the phone reaction in this reaction. We have solid lithium hydride, reacting with Hydrofluoric acid. Remember to determine the products we break up our reactants into their respective ions. Lithium is a group one A. So it's plus one hydride is minus one, this is an acid. So it breaks up into our hydrogen ion plus fluoride ion. This is gonna be a double displacement reaction. So the hydrogens will combine together to give us H two gas and the lithium and fluid will combine together to give us lithium fluoride aqueous. We need to balance this out. So let's see, we have one lithium on each side, we have two hydrogens on each side and we have one fluoride on each side. So in fact, we're already done, this is our balanced reaction.
3
concept
From Metal and Acid
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52s
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Now, we can also get the production of H two gas from a metal and an acid. Here, we're gonna say when reactive metals react with sulfuric acid or hydrochloric acid, the metal is oxidized and H two is formed. In this example. Here, we have our metal solid reacting with H plus which is coming from either sulfuric acid or hydrochloric acid. They will produce H two gas as a product. And the metal itself is going to be ionized here. If it's in group one A to become plus one in charge and to balance this out, we have two hydrogens on the product side, but only one on the reaction side. So we have to place a coefficient of two here. This will represent our oxidation of a group one, a metal by an acid in order to generate hydrogen gas as a product.
4
example
Production of Hydrogen Example
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Here. It says in this example, complete and balance the following reaction here, we have aluminum solid reacting with hydrochloric acid. We know that this is going to generate H two as a product. So we can already put H two here as a product. Now to determine the ionic compound that's going to be formed, we're gonna say that aluminum is in group three A. So it's going to be three plus in charge chlorine is a group seven A. So it's minus one. Remember when the numbers in the charges are different, they don't cancel out, they crisscross. So three comes here and one comes here that will give us aluminum chloride as a product. Now, here we need to balance this out in order to do that. Um I'm going to put, let's see, we have three chins here, but only one here. But if I put a three here, the hydrogens would still not be balanced. We'd have three hydrogens here and then two over here. So we think about what's the lowest common multiple? The answer is six. So I'm gonna put a six here which gives us six chlorine and six hydrogens to balance out the number of hydrogens. I put a three here. So my hydrogens are balanced to balance out my chlorine. I need to put a two here two times or gives me six chlorine. But now we have two aluminums on the product side. So I'd have to put a two here here. This represents my balanced chemical reaction between aluminum solid and hydrochloric acid.
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Problem
Problem
Complete and balance given reaction.
BaH2(s) + H2O(l) →
A
BaH2(s) + 2 H2O(l) → 2 O2(g) + BaH4(aq)
B
BaH2(s) + 2 H2O(l) → 2 H2O2(l) + Ba(s)
C
2 BaH2(s) + 2 H2O(l) → 2 Ba(OH)2(aq)
D
BaH2(s) + 2 H2O(l) → 2 H2(g) + Ba(OH)2(aq)
6
Problem
Problem
Complete and balance given reaction.
Zn(s) + H2SO4(aq) →
A
2 Zn(s) + H2SO4(aq) → H2(g) + Zn2SO4(aq)
B
Zn(s) + H2SO4(aq) → H2(g) + ZnSO4(aq)
C
Zn(s) + 2 H2SO4(aq) → 2 H2(g) + Zn(SO4)2(aq)
D
Zn(s) + 3 H2SO4(aq) → 3 H2(g) + Zn(SO4)3(aq)
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