Amide Formation - Video Tutorials & Practice Problems
Get help from an AI Tutor
Ask a question to get started.
1
concept
Amide Formation
Video duration:
1m
Play a video:
In this video we're going to talk about amide formation. Now, under this type of reaction, a carboxylic acid and an amine undergo a condensation reaction to form an amide. Now recall, a condensation reaction results in the loss of water. To do this, the carboxylic acid loses its Oh group or Oh portion, and the amine nitrogen loses its 1 hydrogen. Okay, so for this to work the nitrogen needs to possess at least 1 hydrogen. Now, here for this to start we need an H+ catalyst. Okay. So it jump starts this whole process. If we take a look here at a typical amide formation general reaction, we have our carboxylic acid, and remember squiggly lime means it's connected to something else which we don't care about at this moment. And then we have our amine, which again, it also has a squiggly line meaning it's connected to something else. Again, we're not concerned with that. We're focusing on the carboxylic acid portion and the amine portion. We're going to lose water, so the Oh from the carboxylic acid, and the H from the amine, we lose those to produce water. This carbon needs to make up for the bond it just lost, and so do this nitrogen. So what they do is they bond to each other, and in that way we create an amide. Remember an amide is when we have a carbonyl connected, single bonded to a nitrogen group. Right? So this would be how we form an amide through a condensation reaction between a carboxylic acid and an amine.
2
example
Amide Formation Example
Video duration:
48s
Play a video:
Determine the amide product form when 4 Methylpentanoic acid reacts with butylamine. Now, we know that the carboxylic acid and the amine will undergo a condensation reaction, where we lose the o h from the carboxylic acid, and what are the hydrogens from the amine? What's left behind connects together to form our amide product. So here we'd have our carbonyl, we're making the amide connection. Now this nitrogen loses one of its H's, but it still has another one, and it's still connected to this butyl chain. So this would represent our amide product again formed through the condensation reaction of our starting carboxylic acid and amine.
3
Problem
Problem
Predict the amide product formed when 2,2-dimethylpropanoic acid reacts with dimethylamine.