Writing Formulas of Coordination Compounds - Video Tutorials & Practice Problems
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concept
Writing Formulas
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Writing formulas from names. We follow three main rules. Rule one is that the cat ion is written before the anion. So remember the C could be either a counter ion or complex ion, same thing with the anion. Next, the transition metal is written before your ligands when it comes to our complex ion, and then finally, neutral ligands are written before amniotic ligands, both in alphabetical order. And this deals with also our complex ion. So we're gonna use these three main rules when writing the formula for any of these coordinations complexes or coordinations compounds.
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example
Writing Formulas of Coordination Compounds Example
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3m
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Provide a formula for tri aqua di bromo, carbonyl manganese three chlorite. All right. So first, we need to identify the cat ion and the anion. That's the easy part because remember when it comes to naming the whole entire coordinating compound, there's a space that separates our cat ion name from the anion name. So this first part would have to be our cat ion because C ions are written first. And so the chlorine would have to be our anion. Next, we list formulas of metals ligands and the counter ion. So here, let's look at this. We have uh let's see, manganese three, remember the transition metals written first. So manganese three is MN three plus. Then we have tri aqua aqua is water and there's three of them. So put it in parentheses. Let's see. Next, we have di bromo. So that's two BROM means right, there's two of them. And then we have carbonel which is CEO and let's see, all right is co two minus one. Next step three write formula of the complex ion and identify its charge, write transition metal before the ligands, write neutral ligands before antic ligands, both in alphabetical order. So let's just do that first. All right. So what do we have, we have manganese three plus and let's see, we write this alphabetical order. Let's see. So we're going to say here we have, see aqua is neutral, then we have bromide ion and then we have our carbon. So the neutral ones are aqua and carbonel. Remember the neutral ones comes first. So A before C, so A was written first. So a 20 parenthesis three, then we're gonna write co and then bromo, even though B comes before C, it's antic in nature. So it can't be written before Carbonel. So we write BR here and there's two of them. It's a complex ion. So we're gonna place it in brackets and we need the charge of it. All right. So we just have to add up everything we have three plus from the manganese water is neutral. Carbonel is neutral. So they don't contribute to the overall charge. So we can ignore them. We have two bromide ions. Each one is minus one. So this becomes plus three minus two. So the overall charge of this complex is plus one. Now that we have the complex sign, we move to step four, we add the counter ion to the outside of the bracket of the complex ion. So you're gonna write cion before an ion and then you balance charges. All right. So this is our cat ion. So it's written first chlorite is our anion. So it's written second, the numbers and the charges are the same. So when they combine, they just cancel out. So the formula for this co-ordination compound would be manganese with the three waters, the carb um carbonel, the two bromides and then clo two, this would be our final answer.
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Problem
Problem
Write a formula for following coordination compound: sodium tris(ethylenediamine)oxalatonickelate(I).
A
Na2[Ni(en)3CO2]
B
Na[Ni(NH3)3CO2]
C
Na[Ni(en)3C2O4]
D
Na[Ni(NH3)3C2O4]
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Problem
Problem
What would be the formula for dibromotetracarbonylstannate(IV) sulfate.
A
[Sn(CO)4(Br)2](SO4)2
B
[Sn(CO)4(Br)2]SO4
C
[Sn(C2O4)4(Br)2](SO4)2
D
[Sn(C2O4)4(Br)2]SO4
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