Writing Formulas of Coordination Compounds - Video Tutorials & Practice Problems
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concept
Writing Formulas
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Writing formulas from names, we follow 3 main rules. Rule 1 is that the cation is written before the anion. So remember, the cation could be either a counter ion or complex ion, same thing with the anion. Next, the transition metal is written before your ligands when it comes to our complex ion, and then finally neutral ligands are written before anionic ligands, both in alphabetical order. And this deals with also our complex ion. So we're gonna use these three main roles when writing the formula for any of these coordination complexes or coordination compounds.
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example
Writing Formulas of Coordination Compounds Example
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Provide a formula for tri aquadibromocarbonylmanganese 3chloride. Alright. So first we need to identify the cation and the anion. That's the easy part. Because remember, when it comes to naming the whole entire coordination compound, there's a space that separates our cation name from the anion name. So this first part would have to be our cation, because cations are written first, and so the chlorite would have to be our anion. Next, we list formulas of metals, ligands, and the counter ion. So here, let's look at this. We have, let's see, manganese 3. Remember the transition metals written first, so manganese 3 is m n three plus. Then we have triaqua. Aqua is water, and there's 3 of them, so put it in parentheses. Let's see. Next we have dibromo, so that's 2 bromines. Alright? There's 2 of them. And then we have carbonyl which is c o, And let's see. Chlorite is ClO2-1. Next step, rewrite formula of the complex ion and identify its charge. Write transition metal before the ligands. Write neutral ligands before anionic ligands, both in alphabetical order. So let's just do that first. Alright. So what do we have? We have manganese 3 plus, and let's see, we write this alphabetical order. Let's see. So we're gonna say here we have, let's see, aqua is neutral, then we have bromide ion, and then we have our carbonyl. So the neutral ones are aqua and carbonyl. Remember the neutral ones comes first, so a before c, so aqua is written first, so a 2 o parenthesis 3, then we're gonna write c o, and then bromo, even though b comes before c, it's anionic in nature, so it can't be written before carbonyl. So we write b r here, and there's 2 of them. It's a complex ion, so we're gonna place it in brackets, and we need the charge of it. Alright. So we just have to add up everything. We have 3 plus from the manganese. Water is neutral, carbonyl is neutral, so they don't contribute to the overall charge, so we can ignore them. We have 2 bromide ions, each one is minus 1. So this becomes plus 3 minus 2. So the overall charge of this complex ion is plus 1. Now that we have the complex ion, we move to step 4. We add the counter ion to the outside of the bracket of the complex ion. So you're gonna write cation before anion, and then you balance charges. Alright. So this is our cation, so it's written first. Chlorite is our anion, so it's written second. The numbers and the charges are the same, so when they combine, they just cancel out. So the formula for this coordination compound would be manganese with the 3 waters, the carb carbonyl, the 2 bromides, and then cl02. This would be our final answer.
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Problem
Problem
Write a formula for following coordination compound: sodium tris(ethylenediamine)oxalatonickelate(I).
A
Na2[Ni(en)3CO2]
B
Na[Ni(NH3)3CO2]
C
Na[Ni(en)3C2O4]
D
Na[Ni(NH3)3C2O4]
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Problem
Problem
What would be the formula for dibromotetracarbonylstannate(IV) sulfate.