8. Thermochemistry
Enthalpy of Formation
17PRACTICE PROBLEM
The following reaction shows the atomization of HCl where the H–Cl bond is broken to produce H and Cl atoms in the gas phase:
HCl(g) → H(g) + Cl(g)
How is this reaction similar or different from the reverse of the standard enthalpy of formation of HCl(g)?
The following reaction shows the atomization of HCl where the H–Cl bond is broken to produce H and Cl atoms in the gas phase:
HCl(g) → H(g) + Cl(g)
How is this reaction similar or different from the reverse of the standard enthalpy of formation of HCl(g)?
ANSWERS OPTIONS
A
The two reactions are the same.
B
The atomization of HCl is the reverse reaction of the formation equation.
C
In atomization, the products are in atomic form. In the reverse of the formation equation, the products are the standard form of the elements.
D
In atomization, the products are the standard form of the elements. In the reverse of the formation equation, the products are in atomic form.