Provide the net ionic equation that occurs when the following ...

Question

Provide the net ionic equation that occurs when the following aqueous compounds are mixed together:

Copper (II) Bromide and Lithium Hydroxide

Accepted Answer

Here in this practice question, it says, provide the net ionic equation that occurs when the following aqueous compounds are mixed together. Alright. So they're telling us here that copper 2 bromide and lithium hydroxide are aqueous compounds. So here, copper 2 means we have c u 2 plus. Bromide is in group 7 a, so it's minus 1. We have lithium which is in group 1 a, so it's plus 1. And then we have hydroxide which is a polyatomic ion so it's o h minus 1. So here for our reactants, what we have initially is CUBr2 aqueous plus l I o h aqueous. Here, we have to determine what our products will be. So here we have to switch partners. This minus 1 and this plus 1 are attracted to one another. Because the numbers in their charges are the same, when they combine, they just cancel out. So here we have lithium bromide. Based on our solubility rules, we know that anything connected to group 1 a ion is aqueous. Then plus, we have copper 2 ion and we have a hydroxide ion combining. The numbers in their charges now though are different, so they don't just simply cancel out. Remember, when the numbers are different, they crisscross. So here that would give me cu0h2. Remember, hydroxide is normally a precipitate. The only way for it to become aqueous is if it's connected to anything from gynne cash, like group 1 a or acetate or nitrate, or if it's connected to c b s, calcium, barium, or strontium. So here it's gonna be a solid. If you don't quite remember your solubility rules, make sure you go back and take a look at them. So here this represents our molecular equation. We still have to balance it. We're going to say here we have 2 bromines, so we're gonna put a 2 here, but then that gives me 2 lithiums so I have to put a 2 here. Here it's balanced out because this 2 would distribute it to distribute to this o h, which is how we have 2 o h's here. So here this represents my balanced molecular equation. Next what we're going to do is we're going to change our balanced molecular equation into a complete ionic equation. In a complete ionic equation, we break up only the aqueous compounds and make sure you distribute these coefficients to the number of ions that you create. So here, we're gonna have 1 copper 2+aqueousplus2bromideaqueousplus2 lithiumplus 1 aqueous plus 2 hydroxide aqueous produces 2 lithium plus 1 aqueous plus 2 bromide aqueous. And remember, this is a solid, so it stays together. So plus 1 copper 2 hydroxide solid. So this represents our complete ionic equation. Lastly, we need to give the net ionic equation. Remember, in the net ionic equation, you remove spectator ions. The ions that look exactly the same because they exist as both products and reactants. So here these are spectator ions. They will not be brought down. So what's left would be copper 2++2hydroxides gives me 1 copper hydroxo copper 2 hydroxide solid. So that there would represent our net ionic equation based on the 2 aqueous compounds given to us in the very

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Provide the net ionic equation that occurs when the following aqueous compounds are mixed together:
Copper (II) Bromide and Lithium Hydroxide

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