In a reaction, 0.50 mol of HCl is neutralized by NaOH according to the equation: HCl + NaOH → NaCl + H2O. How many moles of NaOH are required to react completely with the acid?

• A. 0.50 mol
• B. 1.00 mol
• C. 0.25 mol
• D. 2.00 mol

Answer: (A)

Verified step by step guidance

1. Write the balanced chemical equation for the reaction: \(\text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O}\).
2. Identify the mole ratio between HCl and NaOH from the balanced equation. Here, 1 mole of HCl reacts with 1 mole of NaOH.
3. Use the given amount of HCl (0.50 mol) and apply the mole ratio to find the moles of NaOH required: \(\text{moles of NaOH} = 0.50 \text{ mol HCl} \times \frac{1 \text{ mol NaOH}}{1 \text{ mol HCl}}\).
4. Calculate the moles of NaOH needed to completely neutralize the given amount of HCl based on the mole ratio.
5. Conclude that the moles of NaOH required are equal to the moles of HCl, which is 0.50 mol.