Given that the energy of a single photon is 1.48 × 10^{-15} J, what is the frequency of the light? (Planck's constant h = 6.626 × 10^{-34} J·s)

• A. 4.48 × 10^{19} Hz
• B. 1.48 × 10^{15} Hz
• C. 9.98 × 10^{16} Hz
• D. 2.23 × 10^{18} Hz

Answer: (D)

Verified step by step guidance

1. Recall the relationship between the energy of a photon and its frequency, given by the equation \(E = h \nu\), where \(E\) is the energy of the photon, \(h\) is Planck's constant, and \(\nu\) is the frequency of the light.
2. Rearrange the equation to solve for the frequency \(\nu\): \(\nu = \frac{E}{h}\).
3. Substitute the given values into the equation: \(E = 1.48 \times 10^{-15}\) J and \(h = 6.626 \times 10^{-34}\) J·s.
4. Perform the division to find the frequency: \(\nu = \frac{1.48 \times 10^{-15}}{6.626 \times 10^{-34}}\) Hz.
5. Express the result in scientific notation to match the format of the answer choices.