How many kilocalories are required to heat 100.00 g of water from 34.2 °C to 96.5 °C? (Specific heat of water = 1.00 cal/g·°C)

• A. 3.45 kcal
• B. 9.85 kcal
• C. 12.5 kcal
• D. 6.23 kcal

Answer: (D)

Verified step by step guidance

1. Identify the given quantities: mass of water (m) = 100.00 g, initial temperature (T_i) = 34.2 °C, final temperature (T_f) = 96.5 °C, and specific heat capacity (c) = 1.00 cal/g·°C.
2. Calculate the temperature change (\Delta T) using the formula: \(\Delta T = T_f - T_i\).
3. Use the heat energy formula to find the amount of heat (q) in calories: \(q = m \times c \times \Delta T\).
4. Convert the heat energy from calories to kilocalories by dividing by 1000, since 1 kcal = 1000 cal.
5. Express the final answer as the number of kilocalories required to heat the water from 34.2 °C to 96.5 °C.