A photon of light emitted by a heated atom has an energy of 3.285 x 10^-19 J. What is the frequency of this photon in Hz?

• A. 4.95 x 10^14 Hz
• B. 2.45 x 10^14 Hz
• C. 1.23 x 10^15 Hz
• D. 6.63 x 10^14 Hz

Answer: (A)

Verified step by step guidance

1. Start by recalling the relationship between the energy of a photon and its frequency, given by the equation: $E=hf$, where $E$ is the energy of the photon, $h$ is Planck's constant, and $f$ is the frequency.
2. Planck's constant $h$ is approximately $6.626\times 10^-34\text{J·s}$. Use this value in the equation.
3. Rearrange the equation to solve for frequency $f$: $f=\frac{E}{h}$.
4. Substitute the given energy value $3.285\times 10^-19\text{J}$ and Planck's constant into the equation: $f=\frac{3.285}{\times }$.
5. Calculate the frequency $f$ using the values substituted into the equation. This will give you the frequency in Hz.