How much heat energy is required to melt 1 gram of ice at 0°C to liquid water at 0°C?

• A. 4.18 J
• B. 334 J
• C. 2260 J
• D. 100 J

Answer: (B)

Verified step by step guidance

1. Identify the physical process: melting ice at 0°C to liquid water at 0°C is a phase change that requires heat energy called the heat of fusion.
2. Recall the formula to calculate heat energy for a phase change: \(Q = m \times \Delta H_{fus}\), where \(Q\) is the heat energy, \(m\) is the mass, and \(\Delta H_{fus}\) is the heat of fusion.
3. Use the given mass of ice, which is 1 gram, and find the heat of fusion of water (ice) from a reference table, which is approximately 334 J/g.
4. Substitute the values into the formula: \(Q = 1\,g \times 334\,\frac{J}{g}\).
5. Calculate the product to find the heat energy required to melt 1 gram of ice at 0°C to liquid water at 0°C.