What is the mass, in grams, of 3.09 × 10^{24} atoms of sulfur (atomic mass = 32.07 g/mol)?

• A. 98.7 g
• B. 164.8 g
• C. 15.5 g
• D. 32.1 g

Answer: (B)

Verified step by step guidance

1. Identify the given information: the number of sulfur atoms is \$3.09 \times 10^{24}$ atoms, and the atomic mass of sulfur is 32.07 g/mol.
2. Recall that 1 mole of any substance contains Avogadro's number of atoms, which is \$6.022 \times 10^{23}$ atoms/mol.
3. Calculate the number of moles of sulfur atoms by dividing the given number of atoms by Avogadro's number using the formula: \(\text{moles} = \frac{\text{number of atoms}}{6.022 \times 10^{23}}\).
4. Convert the moles of sulfur to mass in grams by multiplying the number of moles by the atomic mass of sulfur: \(\text{mass} = \text{moles} \times 32.07 \, \text{g/mol}\).
5. The result from the previous step will give the mass of sulfur in grams corresponding to \$3.09 \times 10^{24}$ atoms.