Write an electron configuration for ion of Tungsten (IV).

• A. [Xe]6s²4f¹⁴5d⁴
• B. [Xe]6s²4f¹⁴
• C. [Xe]6s²4f¹⁴5d⁸
• D. [Xe]4f¹⁴5d²

Answer: (D)

Verified step by step guidance

1. Identify the neutral atom's electron configuration: Tungsten (W) has an atomic number of 74, so its electron configuration is [Xe]6s^24f^145d^4.
2. Determine the charge of the ion: Tungsten (IV) indicates a +4 charge, meaning it has lost 4 electrons.
3. Remove electrons starting from the outermost shell: Electrons are removed first from the 6s orbital, then from the 5d orbital.
4. Remove 2 electrons from the 6s orbital: This changes the configuration to [Xe]4f^145d^4.
5. Remove 2 more electrons from the 5d orbital: This results in the final electron configuration of [Xe]4f^145d^2 for the W^4+ ion.