What is the molarity of a solution containing 147 g of H2SO4 dissolved in 0.75 L of solution? (Molar mass of H2SO4 = 98 g/mol)

• A. 1.5 M
• B. 0.5 M
• C. 2.0 M
• D. 1.0 M

Answer: (C)

Verified step by step guidance

1. Identify the given information: mass of H2SO4 = 147 g, volume of solution = 0.75 L, and molar mass of H2SO4 = 98 g/mol.
2. Calculate the number of moles of H2SO4 using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{147\ \text{g}}{98\ \text{g/mol}}\).
3. Use the definition of molarity, which is moles of solute per liter of solution: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
4. Substitute the values into the molarity formula: \(M = \frac{\text{moles calculated in step 2}}{0.75\ \text{L}}\).
5. Perform the division to find the molarity of the solution.