At standard temperature and pressure (STP), what volume is occupied by 2.719 × 10^{13} moles of methane gas (CH_4)?

• A. 6.09 × 10^{14} L
• B. 5.44 × 10^{13} L
• C. 1.22 × 10^{15} L
• D. 2.72 × 10^{13} L

Answer: (A)

Verified step by step guidance

1. Recall that at standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. This is a key concept in gas laws and molar volume.
2. Identify the given quantity: the number of moles of methane gas, which is \$2.719 \times 10^{13}$ moles.
3. Use the molar volume relationship to find the total volume occupied by the gas. The formula is: \(\text{Volume} = \text{moles} \times 22.4\, \text{L/mol}\).
4. Substitute the given number of moles into the formula: \(\text{Volume} = 2.719 \times 10^{13} \times 22.4\) liters.
5. Perform the multiplication to find the volume in liters. This will give you the volume occupied by the methane gas at STP.