How many atoms of fluorine are present in 5.6 × 10^{22} molecules of MgF_2?

• A. 1.68 × 10^{23}
• B. 1.12 × 10^{23}
• C. 2.8 × 10^{22}
• D. 5.6 × 10^{22}

Answer: (B)

Verified step by step guidance

1. Identify the number of fluorine atoms in one molecule of magnesium fluoride (MgF_2). Since the formula is MgF_2, each molecule contains 2 fluorine atoms.
2. Write down the given number of MgF_2 molecules: \$5.6 \times 10^{22}$ molecules.
3. Calculate the total number of fluorine atoms by multiplying the number of molecules by the number of fluorine atoms per molecule: \(\text{Number of F atoms} = 5.6 \times 10^{22} \times 2\).
4. Perform the multiplication of the coefficients and add the exponents of 10 accordingly (do not calculate the final value here, just set up the expression).
5. Express the final answer in scientific notation to represent the total number of fluorine atoms present in the given sample.