What is the mass in grams of EDTA (molar mass = 292 g/mol) required to prepare 500 mL of a 0.01 M EDTA solution?

• A. 2.92 g
• B. 1.46 g
• C. 0.146 g
• D. 0.292 g

Answer: (B)

Verified step by step guidance

1. Identify the given information: volume of solution (V) = 500 mL, molarity (M) = 0.01 M, and molar mass (MM) of EDTA = 292 g/mol.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter: \(V (L) = \frac{500}{1000} = 0.5\) L.
3. Calculate the number of moles of EDTA needed using the molarity formula: \(\text{moles} = M \times V = 0.01 \times 0.5\).
4. Convert moles of EDTA to mass in grams using the molar mass: \(\text{mass} = \text{moles} \times MM = (0.01 \times 0.5) \times 292\) g.
5. The result from the previous step gives the mass of EDTA required to prepare 500 mL of a 0.01 M solution.