Identify the reactants and products in the given reaction: AgNO\_3 (aq) reacts with LiBr (aq) to form AgBr (s) and LiNO\_3 (aq).
Write the full ionic equation by dissociating all strong electrolytes (soluble salts) into their ions: AgNO\_3 (aq) dissociates into Ag\^+ (aq) and NO\_3\^- (aq), LiBr (aq) dissociates into Li\^+ (aq) and Br\^- (aq), and LiNO\_3 (aq) dissociates into Li\^+ (aq) and NO\_3\^- (aq).
Identify the spectator ions, which are ions that appear unchanged on both sides of the equation. In this case, Li\^+ (aq) and NO\_3\^- (aq) are spectator ions.
Remove the spectator ions from the full ionic equation to write the net ionic equation, which includes only the species that undergo a chemical change.
Express the net ionic equation showing the formation of the solid precipitate AgBr (s) from its ions: Ag\^+ (aq) + Br\^- (aq) → AgBr (s).