Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Which of the following bonds is the most polar?
A
H–I
B
H–F
C
H–Br
D
H–Cl
Verified step by step guidance
1
Understand that bond polarity depends on the difference in electronegativity between the two atoms forming the bond. The greater the difference, the more polar the bond.
Recall the electronegativity values of the halogens involved: Fluorine (F) has the highest electronegativity, followed by Chlorine (Cl), Bromine (Br), and Iodine (I). Hydrogen (H) has a lower electronegativity than all of these.
Calculate or compare the electronegativity differences for each bond: H–F, H–Cl, H–Br, and H–I. Use the formula: \(\Delta EN = |EN_{\text{halogen}} - EN_{\text{H}}|\).
Rank the bonds based on their electronegativity differences. The bond with the largest \(\Delta EN\) is the most polar.
Conclude that since Fluorine has the highest electronegativity, the H–F bond has the greatest electronegativity difference and is therefore the most polar bond among the options.