How many moles of solute are present in 300. mL of a 0.60 M solution of NaOH?

• A. 0.030 mol
• B. 0.50 mol
• C. 0.60 mol
• D. 0.18 mol

Answer: (D)

Verified step by step guidance

1. Identify the given information: volume of solution = 300. mL and molarity (M) = 0.60 mol/L. Remember to convert volume from milliliters to liters because molarity is expressed in moles per liter.
2. Convert the volume from milliliters to liters using the conversion factor: \$1\, \text{L} = 1000\, \text{mL}\(. So, \)300\, \text{mL} = \frac{300}{1000} = 0.300\, \text{L}$.
3. Recall the definition of molarity: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\). Rearranged to find moles of solute, it becomes \(\text{moles of solute} = M \times \text{liters of solution}\).
4. Substitute the known values into the equation: \(\text{moles of solute} = 0.60\, \text{mol/L} \times 0.300\, \text{L}\).
5. Calculate the product to find the number of moles of NaOH in the solution.