At standard temperature and pressure (STP), which volume will be occupied by a gas containing 6.02 × 10^{23} atoms?

• A. 0.0821 L
• B. 11.2 L
• C. 22.4 L
• D. 1.00 L

Answer: (C)

Verified step by step guidance

1. Recall that at standard temperature and pressure (STP), one mole of any ideal gas occupies a volume of 22.4 liters. This is a fundamental concept in gas laws.
2. Identify the number of atoms given: 6.02 × 10^{23} atoms. This number is Avogadro's number, which corresponds to one mole of particles (atoms, molecules, etc.).
3. Since the problem states the gas contains 6.02 × 10^{23} atoms, it means we have exactly one mole of gas atoms.
4. Use the molar volume of a gas at STP to find the volume occupied by one mole of gas: 22.4 L per mole.
5. Conclude that the volume occupied by the gas containing 6.02 × 10^{23} atoms at STP is 22.4 liters.