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Multiple Choice
In the reaction 3 Na(s) + AlCl_3(aq) → 3 NaCl(aq) + Al(s), which substance is reduced?
A
NaCl(aq)
B
AlCl_3(aq)
C
Al(s)
D
Na(s)
Verified step by step guidance
1
Identify the oxidation states of the elements in the reactants and products to determine which species undergoes reduction.
For sodium (Na) in its elemental form (Na(s)), the oxidation state is 0 because it is in its pure elemental state.
In aluminum chloride (AlCl_3), aluminum (Al) typically has an oxidation state of +3, and chlorine (Cl) has an oxidation state of -1.
In the products, sodium chloride (NaCl) has sodium in the +1 oxidation state and chlorine in the -1 oxidation state, while aluminum (Al) in its elemental form (Al(s)) has an oxidation state of 0.
Reduction is the gain of electrons, which corresponds to a decrease in oxidation state. Compare the oxidation states of aluminum in AlCl_3 (+3) and Al(s) (0) to identify that aluminum is reduced.