If 25.0 mL of a 2.00 M CaCl_2 solution is used, how many moles of CaCl_2 are present?

• A. 0.100 mol
• B. 0.0500 mol
• C. 0.0250 mol
• D. 0.00500 mol

Answer: (B)

Verified step by step guidance

1. Identify the given information: volume of solution (V) = 25.0 mL and molarity (M) = 2.00 M. Remember that molarity is defined as moles of solute per liter of solution.
2. Convert the volume from milliliters to liters because molarity uses liters: use the conversion \$1\, \text{L} = 1000\, \text{mL}\(, so \)V_{\text{L}} = \frac{25.0}{1000}$ liters.
3. Use the molarity formula to find moles of CaCl_2: \(\text{moles} = M \times V_{\text{L}}\).
4. Substitute the values into the formula: multiply the molarity (2.00 M) by the volume in liters (from step 2) to get the number of moles.
5. Interpret the result as the amount of CaCl_2 in moles present in the 25.0 mL solution.