A sample of glucose (C6H12O6) has a molar mass of 180.16 g/mol. What is the percent composition of carbon in glucose?

• A. 39.99%
• B. 44.44%
• C. 33.33%
• D. 53.33%

Answer: (A)

Verified step by step guidance

1. Identify the molar mass of glucose, which is given as 180.16 g/mol.
2. Determine the number of carbon atoms in one molecule of glucose. Since the formula is C6H12O6, there are 6 carbon atoms.
3. Calculate the total mass of carbon in one mole of glucose by multiplying the number of carbon atoms by the atomic mass of carbon (approximately 12.01 g/mol): \$6 \times 12.01$ g/mol.
4. Calculate the percent composition of carbon by dividing the total mass of carbon by the molar mass of glucose and then multiplying by 100 to get a percentage: \(\left( \frac{6 \times 12.01}{180.16} \right) \times 100\)%.
5. Interpret the result as the percent composition of carbon in glucose.