How many grams of LiF are present in 575 mL of a 0.750 M LiF solution?

• A. 8.2 g
• B. 24.6 g
• C. 12.5 g
• D. 16.8 g

Answer: (D)

Verified step by step guidance

1. Identify the given information: volume of solution = 575 mL, molarity (M) = 0.750 mol/L, and the compound is LiF.
2. Convert the volume from milliliters to liters because molarity is in moles per liter: \(\text{Volume (L)} = \frac{575}{1000}\).
3. Calculate the number of moles of LiF using the molarity formula: \(\text{moles} = M \times \text{Volume (L)} = 0.750 \times \frac{575}{1000}\).
4. Find the molar mass of LiF by adding the atomic masses of lithium (Li) and fluorine (F): \(\text{Molar mass of LiF} = \text{atomic mass of Li} + \text{atomic mass of F}\).
5. Calculate the mass of LiF by multiplying the moles by the molar mass: \(\text{mass (g)} = \text{moles} \times \text{molar mass (g/mol)}\).