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Multiple Choice
In the balanced chemical equation for the reaction between acetic acid and sodium carbonate, if the coefficient for sodium acetate (NaC2H3O2) is 2, what is the total number of sodium atoms present in the products side of the equation?
A
3
B
2
C
4
D
1
Verified step by step guidance
1
Write the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium carbonate (Na2CO3). The general form is: 2 CH3COOH + Na2CO3 → 2 NaC2H3O2 + H2O + CO2.
Identify the coefficient of sodium acetate (NaC2H3O2) in the balanced equation, which is given as 2.
Determine the number of sodium (Na) atoms in one formula unit of sodium acetate. Since the formula is NaC2H3O2, there is 1 sodium atom per formula unit.
Multiply the coefficient of sodium acetate by the number of sodium atoms per formula unit to find the total sodium atoms contributed by sodium acetate: 2 × 1 = 2 sodium atoms.
Check if there are any other sodium-containing products on the product side. In this reaction, sodium acetate is the only sodium-containing product, so the total number of sodium atoms on the product side is the number from sodium acetate multiplied by its coefficient.