A solution is made by mixing equal masses of methanol (CH3OH) and water (H2O). Which component will have the greater number of moles in the solution?

• A. Methanol (CH3OH)
• B. Water (H2O)
• C. Cannot be determined without volume information
• D. Both have the same number of moles

Answer: (A)

Verified step by step guidance

1. Identify the given information: equal masses of methanol (CH\_3OH) and water (H\_2O) are mixed. We need to find which component has the greater number of moles.
2. Recall the formula to calculate moles from mass: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
3. Find the molar masses of each component by summing the atomic masses: for methanol (CH\_3OH), calculate \$12.01 + (4 \times 1.008) + 16.00\( g/mol; for water (H\_2O), calculate \)(2 \times 1.008) + 16.00$ g/mol.
4. Since the masses are equal, compare the number of moles by dividing the same mass by each molar mass. The component with the smaller molar mass will have more moles.
5. Conclude which component has the greater number of moles based on the comparison of molar masses.