According to the Bohr model of atomic quantization, what is the energy of photons emitted during an electron transition?

• A. The energy equals the energy of the final level only: E = E_f
• B. The energy equals the sum of the initial and final energy levels: E = E_i + E_f
• C. The energy equals the difference between the initial and final energy levels: E = E_i - E_f
• D. The energy equals the product of the initial and final energy levels: E = E_i imes E_f

Answer: (C)

Verified step by step guidance

1. Understand that in the Bohr model, electrons occupy discrete energy levels, each with a specific energy value denoted as \(E_i\) for the initial level and \(E_f\) for the final level.
2. Recognize that when an electron transitions from a higher energy level (\(E_i\)) to a lower energy level (\(E_f\)), it emits a photon whose energy corresponds to the difference between these two levels.
3. Express the energy of the emitted photon as the difference between the initial and final energy levels: \(E = E_i - E_f\).
4. Note that this energy difference corresponds to the photon's energy, which can also be related to its frequency (\(\nu\)) and wavelength (\(\lambda\)) through the equation \(E = h \nu = \frac{hc}{\lambda}\), where \(h\) is Planck's constant and \(c\) is the speed of light.
5. Conclude that the correct expression for the energy of the emitted photon during an electron transition in the Bohr model is the difference between the initial and final energy levels, not their sum, product, or just the final energy.