At standard temperature and pressure (STP), what is the volume occupied by 1 mole of an ideal gas?

• A. 0.0821 L
• B. 1.00 L
• C. 273 L
• D. 22.4 L

Answer: (D)

Verified step by step guidance

1. Recall that at standard temperature and pressure (STP), which is defined as 0°C (273 K) and 1 atm pressure, one mole of an ideal gas occupies a specific volume.
2. Use the ideal gas law equation: \(P \times V = n \times R \times T\), where \(P\) is pressure, \(V\) is volume, \(n\) is number of moles, \(R\) is the ideal gas constant, and \(T\) is temperature in Kelvin.
3. Substitute the known values for STP: \(P = 1\) atm, \(n = 1\) mole, \(R = 0.0821\) L·atm/(mol·K), and \(T = 273\) K into the ideal gas law.
4. Rearrange the ideal gas law to solve for volume \(V\): \(V = \frac{n \times R \times T}{P}\).
5. Calculate the volume by plugging in the values: \(V = \frac{1 \times 0.0821 \times 273}{1}\), which will give the volume occupied by 1 mole of an ideal gas at STP.