Calculate the experimental mass % of c and h in the unknown liqui...

Question

Calculate the experimental mass % of c and h in the unknown liquid used in the experiment.

Accepted Answer

Hi everyone said we have been to which is H9 H. We have an unlabeled bottle which is expected to contain this liquid. Whereas to identify if the identity of the liquid is indeed and all is 1.55 g of the liquid produces 1.84 g of H 20 and 3.679 g of C 02. We need to first calculate the mass percent of carbon and hydrogen in beauty in all all that. The mass percent, the mass of the element by the mass of the compound Times 100%. Last percent of carbon, it was a mass of carbon by the mass A C four H nine H 100% the mass percent of carbon. He goes 12. Times four Because there's four carbon in Britain, all divided by the molar mass of beautiful And this is four times 12.01. one g Plus 10 was 1.008 g. That's 15.999 g. And you get 74 12 g Times 100%. Can we get 64.82%. And then the mass percent of hydrogen is a mass of hydrogen by the mass regional Times 100%. A mass percent of hydrogen People's 1.008 Times 10 because there's 10 hydrogen and beautiful five x 74. 1, 2 100%. We get 13.6%. So now I need to calculate the masses of carbon and hydrogen in the sample assuming it is beautiful. We need to convert a mass percentages into decimals and multiplied by the mass of the liquid That produced A. O. and CO two. Carbon 0.6482. That's 1.55. Get 1.005g hydrogen 0.13 zero was 1. Is your .211g. Now we can calculate the mass percentage of carbon in co two and hydrogen in H20. The mass percent of carbon because the mass of carbon by the by the mass C 100% the mass percent of carbon. It's 12. By the Molar Mass which is 0.1 Times eight, The mass percent of hydrogen get the mass of hydrogen by by the mask AC 02 or it's too out Times 100%. The mass percent of hydrogen Is 1.008 times two there's two hydrogen and the O By by the Molar mass of H20, which is 18.02 Times 100%. And we get 11.19%. So we need to convert the mass percentage into decimals and most part by the masses of H and CO2 produced by the liquid of the carbon 0.2729 On 3.679. And we get 1.005 g hydrogen 0.1119 Times 1. And get 0.211 g. And now, since the massive carbon and hydrogen and c. 02 and H 20 produced by the liquid is the same as a massive carbon and hydrogen, a sample we're going to assume it is beautiful and it's gonna be, yes, the liquid is beautiful. Thanks for watching my video and I hope it was helpful.

Calculate the experimental mass % of c and h in the unknown liquid used in the experiment.

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