Based on the octet rule, boron will most likely form which type of ion?

• A. B^{2-}
• B. B^{3-}
• C. B^{2+}
• D. B^{3+}

Answer: (D)

Verified step by step guidance

1. Recall that the octet rule states atoms tend to gain, lose, or share electrons to achieve a full outer shell of 8 electrons, similar to the nearest noble gas configuration.
2. Determine the number of valence electrons in a neutral boron atom. Boron has an atomic number of 5, so it has 3 valence electrons in its outer shell.
3. Consider how boron can achieve an octet: it can either gain electrons to fill its outer shell or lose electrons to empty its outer shell and reach the electron configuration of the previous noble gas.
4. Since gaining 5 electrons to reach 8 is highly unlikely for boron, it is more favorable for boron to lose its 3 valence electrons, resulting in a \(B^{3+}\) ion.
5. Therefore, based on the octet rule and boron's position in the periodic table, the most likely ion formed is \(B^{3+}\).