What is the molarity of a solution prepared by dissolving 2.0 moles of sodium bromide (NaBr) in 200 mL of solution?

• A. 4.0 M
• B. 0.40 M
• C. 10.0 M
• D. 0.10 M

Answer: (C)

Verified step by step guidance

1. Identify the formula for molarity, which is the number of moles of solute divided by the volume of the solution in liters: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
2. Note the given values: moles of sodium bromide (NaBr) = 2.0 moles, and volume of solution = 200 mL.
3. Convert the volume from milliliters to liters because molarity requires volume in liters: \$200\ \text{mL} = \frac{200}{1000} = 0.200\ \text{L}$.
4. Substitute the values into the molarity formula: \(M = \frac{2.0\ \text{moles}}{0.200\ \text{L}}\).
5. Calculate the molarity by dividing the moles by the volume in liters to find the concentration of the NaBr solution.