In stoichiometry, how do you determine the mole ratio between $N_2$ and $H_2$ in the balanced equation $N_2+3H_2\to 2N_{H_3}$?

• A. Use the coefficients in the balanced equation; the mole ratio is $\frac{1 \mathrm{mol} N_2}{3 \mathrm{mol} H_2}$.
• B. Use molar masses; the mole ratio is $\frac{28}{2}$.
• C. Use the product coefficients; the mole ratio is $\frac{2 \mathrm{mol} N_2}{2 \mathrm{mol} H_2}$.
• D. Use the subscripts in the formulas; the mole ratio is $\frac{2 \mathrm{mol} N_2}{2 \mathrm{mol} H_2}$.

Answer: (A)