What is the molarity of a 0.30 L solution containing 43 g of H_2SO_4? (Molar mass of H_2SO_4 = 98 g/mol)

• A. 3.0 M
• B. 1.5 M
• C. 0.15 M
• D. 0.49 M

Answer: (B)

Verified step by step guidance

1. Identify the formula for molarity, which is the number of moles of solute divided by the volume of the solution in liters: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
2. Calculate the number of moles of \(H_2SO_4\) using its given mass and molar mass: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{43\,\text{g}}{98\,\text{g/mol}}\).
3. Use the volume of the solution provided, which is 0.30 L, as the denominator in the molarity formula.
4. Substitute the calculated moles and the volume into the molarity formula: \(M = \frac{\text{moles of } H_2SO_4}{0.30\,\text{L}}\).
5. Perform the division to find the molarity, which will give the concentration of the \(H_2SO_4\) solution in moles per liter (M).