What is the molarity of a solution containing 5.60 mol of sodium carbonate (Na_2CO_3) dissolved in 1500 mL of solution?

• A. 0.27 M
• B. 0.93 M
• C. 8.40 M
• D. 3.73 M

Answer: (D)

Verified step by step guidance

1. Identify the given information: the amount of solute (sodium carbonate, Na_2CO_3) is 5.60 mol, and the volume of the solution is 1500 mL.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \$1\,\text{L} = 1000\,\text{mL}\(, so \)1500\,\text{mL} = \frac{1500}{1000} = 1.5\,\text{L}$.
3. Recall the formula for molarity (\(M\)), which is the number of moles of solute divided by the volume of the solution in liters: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\)
4. Substitute the known values into the molarity formula: \(M = \frac{5.60\,\text{mol}}{1.5\,\text{L}}\)
5. Perform the division to find the molarity of the sodium carbonate solution.