A solution has a molarity of 8.59 M NaCl and a volume of 125 mL. How many moles of NaCl are present in the solution?

• A. 0.93 moles
• B. 0.15 moles
• C. 1.07 moles
• D. 8.59 moles

Answer: (C)

Verified step by step guidance

1. Identify the given information: the molarity (M) of the NaCl solution is 8.59 M, and the volume (V) of the solution is 125 mL.
2. Convert the volume from milliliters to liters because molarity is expressed in moles per liter. Use the conversion: \$1\, \text{L} = 1000\, \text{mL}\(, so \)V (\text{L}) = \frac{125}{1000}$.
3. Recall the definition of molarity: \(M = \frac{\text{moles of solute}}{\text{liters of solution}}\). Rearranged to find moles, it becomes \(\text{moles} = M \times V\).
4. Substitute the known values into the equation: \(\text{moles of NaCl} = 8.59\, \text{M} \times V (\text{L})\).
5. Calculate the product to find the number of moles of NaCl present in the solution.