At STP, what volume of argon gas is occupied by 1.60 grams of argon?

• A. 22.4 L
• B. 0.90 L
• C. 2.24 L
• D. 1.12 L

Answer: (B)

Verified step by step guidance

1. Identify the molar mass of argon (Ar). Argon has an atomic mass of approximately 39.95 g/mol.
2. Calculate the number of moles of argon gas using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{1.60\ \text{g}}{39.95\ \text{g/mol}}\).
3. Recall that at STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters.
4. Calculate the volume occupied by the argon gas using the formula: \(\text{volume} = \text{moles} \times 22.4\ \text{L/mol}\).
5. Substitute the moles calculated in step 2 into the volume formula to find the volume of argon gas at STP.