What is the result when lead (II) nitrate is mixed with potassium bromide in an aqueous solution?

• A. A precipitate of lead (II) bromide forms.
• B. No reaction occurs.
• C. A gas is released.
• D. A precipitate of potassium nitrate forms.

Answer: (A)

Verified step by step guidance

1. Identify the reactants: Lead (II) nitrate (Pb(NO₃)₂) and potassium bromide (KBr).
2. Write the balanced chemical equation for the reaction: Pb(NO₃)₂ (aq) + 2 KBr (aq) → PbBr₂ (s) + 2 KNO₃ (aq).
3. Determine the solubility of the products: Lead (II) bromide (PbBr₂) is insoluble in water and will form a precipitate, while potassium nitrate (KNO₃) is soluble.
4. Conclude that a precipitate of lead (II) bromide forms as a result of the reaction.
5. Verify that no gas is released and no precipitate of potassium nitrate forms, confirming the formation of lead (II) bromide as the precipitate.