How many atoms of zinc are present in 0.60 mol of zinc?

• A. 3.6 × 10^{23} atoms
• B. 1.0 × 10^{24} atoms
• C. 6.0 × 10^{22} atoms
• D. 9.0 × 10^{23} atoms

Answer: (A)

Verified step by step guidance

1. Understand that the problem asks for the number of atoms in a given amount of substance (in moles). The key concept here is the mole, which relates the amount of substance to the number of particles (atoms, molecules, etc.).
2. Recall Avogadro's number, which is the number of atoms in one mole of any element. Avogadro's number is \$6.022 \times 10^{23}$ atoms/mol.
3. Set up the calculation by multiplying the number of moles of zinc by Avogadro's number to find the total number of zinc atoms: \(\text{Number of atoms} = \text{moles of Zn} \times 6.022 \times 10^{23}\) atoms/mol.
4. Substitute the given value of moles (0.60 mol) into the equation: \(\text{Number of atoms} = 0.60 \times 6.022 \times 10^{23}\) atoms.
5. Perform the multiplication to find the number of atoms (do not calculate the final value here, just set up the expression). This will give you the total number of zinc atoms in 0.60 mol.