How many silicon atoms are present in 1.00 g of silicon (Si)? (Atomic mass of Si = 28.09 g/mol)

• A. 3.57 × 10^{21} atoms
• B. 6.02 × 10^{23} atoms
• C. 1.79 × 10^{24} atoms
• D. 2.15 × 10^{22} atoms

Answer: (D)

Verified step by step guidance

1. Identify the given information: mass of silicon (Si) is 1.00 g, and the atomic mass of Si is 28.09 g/mol.
2. Recall that the number of moles of a substance can be calculated using the formula: \(\text{moles} = \frac{\text{mass}}{\text{molar mass}}\).
3. Calculate the number of moles of silicon in 1.00 g by dividing the mass of silicon by its atomic mass: \(\text{moles of Si} = \frac{1.00\ \text{g}}{28.09\ \text{g/mol}}\).
4. Use Avogadro's number, \$6.022 \times 10^{23}\( atoms/mol, to convert moles of silicon to number of atoms: \)\text{number of atoms} = \text{moles of Si} \times 6.022 \times 10^{23}$ atoms/mol.
5. Multiply the moles of silicon by Avogadro's number to find the total number of silicon atoms in 1.00 g.