What volume of 6 M sulfuric acid is required to prepare 500 mL of a 0.30 M solution?

• A. 25 mL
• B. 75 mL
• C. 50 mL
• D. 2.5 mL

Answer: (A)

Verified step by step guidance

1. Start by using the dilution formula, which is \( C_1V_1 = C_2V_2 \), where \( C_1 \) and \( V_1 \) are the concentration and volume of the initial solution, and \( C_2 \) and \( V_2 \) are the concentration and volume of the final solution.
2. Identify the known values: \( C_1 = 6 \text{ M} \), \( C_2 = 0.30 \text{ M} \), and \( V_2 = 500 \text{ mL} \). You need to find \( V_1 \), the volume of the 6 M sulfuric acid solution required.
3. Rearrange the dilution formula to solve for \( V_1 \): \( V_1 = \frac{C_2V_2}{C_1} \).
4. Substitute the known values into the equation: \( V_1 = \frac{0.30 \text{ M} \times 500 \text{ mL}}{6 \text{ M}} \).
5. Calculate \( V_1 \) to find the volume of the 6 M sulfuric acid solution needed to prepare the desired solution.