What volume (in liters) of a 0.25 M solution can be prepared using 0.55 moles of Ca(OH)_2?

• A. 0.23 L
• B. 2.2 L
• C. 0.55 L
• D. 0.14 L

Answer: (B)

Verified step by step guidance

1. Identify the known quantities: the number of moles of Ca(OH)\_2 (0.55 moles) and the molarity of the solution (0.25 M).
2. Recall the definition of molarity (M), which is moles of solute per liter of solution: \(M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}\).
3. Rearrange the molarity formula to solve for volume: \(\text{Volume} = \frac{\text{moles of solute}}{M}\).
4. Substitute the known values into the rearranged formula: \(\text{Volume} = \frac{0.55 \text{ moles}}{0.25 \text{ M}}\).
5. Calculate the volume using the expression above to find the volume of the 0.25 M Ca(OH)\_2 solution that contains 0.55 moles of solute.