(b) What condition must be satisfied so that Qc = Kc?

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Accepted Answer

Hello everyone. Today we are being asked the following question, which of the following is true when our K C or reaction quotient is equal to our Casey or our equilibrium constant. So when this is the case, when they're both equal, this means that the reaction is at equilibrium. So it's not that it's close to two equilibrium. So B is incorrect and it's not that the reactant is greater, the reaction is in equilibrium. And so it's in equilibrium to away where the concentrations are going to be the same. So our answer's gonna be see the reaction is an equilibrium and the concentrations used to calculate Q R the equilibrium concentrations. And so with that, we have answered the question overall, I hope this helped. And until next time.

(b) What condition must be satisfied so that Qc = Kc?

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