A mixture of 8.0 g CH4 and 8.0 g Xe is placed in a container and
...

Question

A mixture of 8.0 g CH4 and 8.0 g Xe is placed in a container and
the total pressure is found to be 0.44 atm. Determine the partial
pressure of CH4.

Accepted Answer

everyone. So here we have heli ops And it contains 85 g of helium Every 15 g of oxygen. Ask calculate the partial pressure of oxygen And the total pressure is 7. atmosphere. We know that a number of malls is even to the mass. Thought about the Mueller mass and the pressure of a gas. Is it the total pressure terms of mole fraction of the gas? So for the pressure of oxygen gas of the total pressure, the mole fraction, which is the number of moles of oxygen gas. About about the total number of malls from moles of helium, 85 brands of helium. And in one mall of helium, The molar mass which is 4.003 grams. And this will give us 21.23 models of helium. The number of most auction gas, 15 grams of option gas. And in one mold of auction gas we have the Mueller mass. And this is to That was a massive auction which is .999 grams. Let's give us 31.998 grams. And we'll get 0.47 balls of oxygen gas. So now I need to find the total number of moles. For in total we're gonna get malls of helium gas plus most of option gas. So for in total We're gonna get 21. balls Plus 0.47 balls. It's going to give us 21 like seven moles total. So for the partial pressure of oxygen gas We're gonna have 7.3 atmosphere. I'm 0.47 balls About by 21.7 balls. So the pressure pressure of option. Gas 0.16 atmosphere. Thanks for watching my video and I hope it was helpful.

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